To find the zeroes of the quadratic equation x² - 2x - 8 = 0, we can use the quadratic formula, which is x = [-b ± sqrt(b² - 4ac)] / 2a.

Here, a = 1 (the coefficient of x²), b = -2 (the coefficient of x), and c = -8 (the constant term).

Step 1: Calculate the discriminant, which is b² - 4ac.
Discriminant = (-2)² - 4*1*(-8) = 4 + 32 = 36.

Step 2: Substitute a, b, and the discriminant into the quadratic formula.
x = [2 ± sqrt(36)] / 2*1
x = [2 ± 6] / 2

So, the zeroes of the equation x² - 2x - 8 = 0 are x = 4 and x = -2.

Question

To find the zeroes of the quadratic equation x² - 2x - 8 = 0, we can use the quadratic formula, which is x = [-b ± sqrt(b² - 4ac)] / 2a.

Here, a = 1 (the coefficient of x²), b = -2 (the coefficient of x), and c = -8 (the constant term).

Step 1: Calculate the discriminant, which is b² - 4ac. 
Discriminant = (-2)² - 4*1*(-8) = 4 + 32 = 36.

Step 2: Substitute a, b, and the discriminant into the quadratic formula.
x = [2 ± sqrt(36)] / 2*1
x = [2 ± 6] / 2

So, the zeroes of the equation x² - 2x - 8 = 0 are x = 4 and x = -2.

Knowee AI · Accepted Answer

To find the zeroes of the quadratic equation x² - 2x - 8 = 0, we can use the quadratic formula, which is x = [-b ± sqrt(b² - 4ac)] / 2a.

Here, a = 1 (the coefficient of x²), b = -2 (the coefficient of x), and c = -8 (the constant term).

Step 1: Calculate the discriminant, which is b² - 4ac. 
Discriminant = (-2)² - 4*1*(-8) = 4 + 32 = 36.

Step 2: Substitute a, b, and the discriminant into the quadratic formula.
x = [2 ± sqrt(36)] / 2*1
x = [2 ± 6] / 2

So, the zeroes of the equation x² - 2x - 8 = 0 are x = 4 and x = -2.

The zeroes of x2–2x –8 are: