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Insert seven rational numbers between 2 and 3

Question

Insert seven rational numbers between 2 and 3

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Solution

Para insertar siete números racionales entre 2 y 3, podemos seguir estos pasos:

  1. Identificar los límites: Los límites son 2 y 3.
  2. Dividir el intervalo: Dividimos el intervalo entre 2 y 3 en ocho partes iguales, ya que necesitamos siete números intermedios.

La fórmula para encontrar los números racionales entre dos números aa y bb es: a+(ba)kn+1 a + \frac{(b - a) \cdot k}{n + 1} donde kk varía de 1 a nn (el número de números que queremos insertar) y n+1n + 1 es el número total de divisiones.

En este caso, a=2a = 2, b=3b = 3, n=7n = 7, y n+1=8n + 1 = 8.

  1. Calcular los números racionales:

Para k=1k = 1: 2+(32)18=2+18=2.125 2 + \frac{(3 - 2) \cdot 1}{8} = 2 + \frac{1}{8} = 2.125

Para k=2k = 2: 2+(32)28=2+28=2.25 2 + \frac{(3 - 2) \cdot 2}{8} = 2 + \frac{2}{8} = 2.25

Para k=3k = 3: 2+(32)38=2+38=2.375 2 + \frac{(3 - 2) \cdot 3}{8} = 2 + \frac{3}{8} = 2.375

Para k=4k = 4: 2+(32)48=2+48=2.5 2 + \frac{(3 - 2) \cdot 4}{8} = 2 + \frac{4}{8} = 2.5

Para k=5k = 5: 2+(32)58=2+58=2.625 2 + \frac{(3 - 2) \cdot 5}{8} = 2 + \frac{5}{8} = 2.625

Para k=6k = 6: 2+(32)68=2+68=2.75 2 + \frac{(3 - 2) \cdot 6}{8} = 2 + \frac{6}{8} = 2.75

Para k=7k = 7: 2+(32)78=2+78=2.875 2 + \frac{(3 - 2) \cdot 7}{8} = 2 + \frac{7}{8} = 2.875

  1. Listar los números racionales:

Los siete números racionales entre 2 y 3 son: 2.125,2.25,2.375,2.5,2.625,2.75,2.875 2.125, 2.25, 2.375, 2.5, 2.625, 2.75, 2.875

This problem has been solved

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