To solve this problem, we need to understand that these are dependent events, meaning the outcome of the first event (drawing a heart) affects the outcome of the second event (drawing a queen).

Step 1: Calculate the probability of drawing a heart first.

There are 13 hearts in a 52-card deck. So, the probability of drawing a heart first is 13/52, which simplifies to 1/4.

Step 2: Calculate the probability of drawing a queen second.

After drawing a heart, there are now 51 cards left in the deck. There are 4 queens in a deck, but since we didn't specify that the queen can't be a heart, we have to consider that one of the queens could have been drawn in the first draw. So, the probability of drawing a queen second is 4/51.

Step 3: Multiply the probabilities together.

The probability of both events happening is found by multiplying the probabilities together. So, the probability of drawing a heart first and then a queen is (1/4) * (4/51) = 4/204 = 1/51.

So, the probability of drawing a heart first, followed by drawing a queen is 1/51.

Question

To solve this problem, we need to understand that these are dependent events, meaning the outcome of the first event (drawing a heart) affects the outcome of the second event (drawing a queen).

Step 1: Calculate the probability of drawing a heart first.

There are 13 hearts in a 52-card deck. So, the probability of drawing a heart first is 13/52, which simplifies to 1/4.

Step 2: Calculate the probability of drawing a queen second.

After drawing a heart, there are now 51 cards left in the deck. There are 4 queens in a deck, but since we didn't specify that the queen can't be a heart, we have to consider that one of the queens could have been drawn in the first draw. So, the probability of drawing a queen second is 4/51.

Step 3: Multiply the probabilities together.

The probability of both events happening is found by multiplying the probabilities together. So, the probability of drawing a heart first and then a queen is (1/4) * (4/51) = 4/204 = 1/51.

So, the probability of drawing a heart first, followed by drawing a queen is 1/51.

Knowee AI · Accepted Answer

To solve this problem, we need to understand that these are dependent events, meaning the outcome of the first event (drawing a heart) affects the outcome of the second event (drawing a queen).

Step 1: Calculate the probability of drawing a heart first.

There are 13 hearts in a 52-card deck. So, the probability of drawing a heart first is 13/52, which simplifies to 1/4.

Step 2: Calculate the probability of drawing a queen second.

After drawing a heart, there are now 51 cards left in the deck. There are 4 queens in a deck, but since we didn't specify that the queen can't be a heart, we have to consider that one of the queens could have been drawn in the first draw. So, the probability of drawing a queen second is 4/51.

Step 3: Multiply the probabilities together.

The probability of both events happening is found by multiplying the probabilities together. So, the probability of drawing a heart first and then a queen is (1/4) * (4/51) = 4/204 = 1/51.

So, the probability of drawing a heart first, followed by drawing a queen is 1/51.

Using a standard 52-card deck, find the following probabilities. Leave your answer as a reduced fraction. If two cards are randomly selected, what is the probability of drawing a heart first, followed by drawing a queen?

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