If A, B, C, D, E, F and G are seven natural numbers, with no three of the seven being equal and Y = A + 2B + 3C + 4D + 5E + 6F + 7G, what is the minimum possible value of Y?
Question
If A, B, C, D, E, F and G are seven natural numbers, with no three of the seven being equal and Y = A + 2B + 3C + 4D + 5E + 6F + 7G, what is the minimum possible value of Y?
Solution
The minimum possible value of Y can be found by assigning the smallest possible natural number to each variable. In mathematics, the set of natural numbers traditionally starts at 1 (not 0).
So, let's assign the smallest possible natural number to each variable:
A = 1 B = 1 C = 1 D = 1 E = 1 F = 1 G = 1
Now, substitute these values into the equation for Y:
Y = A + 2B + 3C + 4D + 5E + 6F + 7G Y = 1 + 21 + 31 + 41 + 51 + 61 + 71 Y = 1 + 2 + 3 + 4 + 5 + 6 + 7 Y = 28
So, the minimum possible value of Y is 28.
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