The energy of a signal x(t) is given by the formula:

E = ∫|x(t)|² dt from -∞ to ∞

If we want to find the energy of the signal x(5t), we substitute 5t for t in the formula:

E = ∫|x(5t)|² dt from -∞ to ∞

However, we need to adjust for the change of variable in the integral. We can do this by introducing a new variable u = 5t. Then du = 5dt, or dt = du/5.

Substituting these into the integral gives:

E = ∫|x(u)|² du/5 from -∞ to ∞

This simplifies to:

E = 1/5 ∫|x(u)|² du from -∞ to ∞

So the energy of the signal x(5t) is 1/5 the energy of the signal x(t).

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The energy of a signal x(t) is given by the formula:

E = ∫|x(t)|² dt from -∞ to ∞

If we want to find the energy of the signal x(5t), we substitute 5t for t in the formula:

E = ∫|x(5t)|² dt from -∞ to ∞

However, we need to adjust for the change of variable in the integral. We can do this by introducing a new variable u = 5t. Then du = 5dt, or dt = du/5.

Substituting these into the integral gives:

E = ∫|x(u)|² du/5 from -∞ to ∞

This simplifies to:

E = 1/5 ∫|x(u)|² du from -∞ to ∞

So the energy of the signal x(5t) is 1/5 the energy of the signal x(t).

Knowee AI · Accepted Answer

The energy of a signal x(t) is given by the formula:

E = ∫|x(t)|² dt from -∞ to ∞

If we want to find the energy of the signal x(5t), we substitute 5t for t in the formula:

E = ∫|x(5t)|² dt from -∞ to ∞

However, we need to adjust for the change of variable in the integral. We can do this by introducing a new variable u = 5t. Then du = 5dt, or dt = du/5.

Substituting these into the integral gives:

E = ∫|x(u)|² du/5 from -∞ to ∞

This simplifies to:

E = 1/5 ∫|x(u)|² du from -∞ to ∞

So the energy of the signal x(5t) is 1/5 the energy of the signal x(t).

If E denotes energy of a signal x(t) then energy of the signal x(5t) is

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