The mathematical formula, F=ma, says that the amount of force necessary to move two bowling balls is twice the force necessary to move one bowling ball True False

Which of Newtons laws applies in the context of one cricket ball being hit only 10 metres, but another cricket ball being hit for six over the top of the grandstand?Group of answer choicesThe rate of change in motion of a body is proportional to the force causing it, and the change takes place in the direction in which the force acts.For every force that is exerted by one body on another, there is an equal and opposite force exerted by the second body on the first.Every body continues in its state of rest or motion in a straight line unless compelled to change that state by external forces exerted upon it.None of the answers given

Newton's second law can be written as which of the following equations1 pointF = m * am = F / aa = F / m

Two forces are acting on an object: a force to the right of 100 N, and a force to the left of 50 N.  State the magnitude and direction of the resultant force which is acting on the object.50 N to the left150 N to the right50 N to the right150 N to the left2A ball which weighs 2 N is dropped from rest.  At a given point in time, as it falls through the air, the upwards force of air resistance which is acting on the ball is equal to 0.5 N.  State the magnitude and direction of the resultant force which is acting on the ball at this point in time.  In answering this question, you may assume that no additional forces are acting on the ball.0.5 N upwards1.5 N downwards2 N downwards1.5 N upwards3In a tug-o-war competition, Team A pull with a force of 900 N, and Team B, with a force of 1.1 kN.  State the magnitude and direction of the resultant of these forces.200 N in the direction of Team A898.9 N in the direction of Team A898.9 N in the direction of Team B200 N in the direction of Team B4A car is free-wheeling down a hill at constant velocity, which means that the resultant force which is acting on it is zero.  The downhill component of its weight is equal to 10 kN, and the force of air resistance which is acting is equal to 6 kN.  Calculate the total frictional force which is acting on the car.  You may assume that no additional forces are acting on it.10 kN16 kN4 kN6 kN5Pauline is pulling a wheeled suitcase through an airport with a force of 200 N which is acting at an angle of 30° to the horizontal.  What will the horizontal component of this force be?Greater than 200 NEqual to 200 NIt is impossible to sayLess than 200 N6The three forces which are acting on an object are in equilibrium with one another.  A student draws a vector diagram to represent these forces.  In it, she connects the vectors so that they are pointing nose-to-tail.  What will this vector diagram look like?An open triangle (one in which the ends of two of the lines do not meet)A line which is made up of three vectors of equal lengthA rectangle which is missing one sideA closed triangle

Two forces are acting on an object: a force to the right of 50 N, and a force to the left of 25 N.  State the magnitude and direction of the resultant force which is acting on the object.25 N to the right75 N to the left25 N to the left75 N to the right2A ball which weighs 1 N is dropped from rest.  At a given point in time, as it falls through the air, the upwards force of air resistance which is acting on the ball is equal to 0.2 N.  State the magnitude and direction of the resultant force which is acting on the ball at this point in time.  In answering this question, you may assume that no additional forces are acting on the ball.0.8 N upwards1.2 N upwards0.8 N downwards1.2 N downwards3In a tug-o-war competition, Team A pull with a force of 800 N, and Team B, with a force of 1.2 kN.  State the magnitude and direction of the resultant of these forces.400 N in the direction of Team B798.8 N in the direction of Team B798.8 N in the direction of Team A400 N in the direction of Team A4A car is free-wheeling down a hill at constant velocity, which means that the resultant force which is acting on it is zero.  The downhill component of its weight is equal to 10 kN, and the force of air resistance which is acting is equal to 6 kN.  Calculate the total frictional force which is acting on the car.  You may assume that no additional forces are acting on it.10 kN4 kN6 kN16 kN

One Newton is the force:Group of answer choicesneeded to accelerate a 1-kg mass at 1 m/s2needed to move a 1-kg mass at 1 m/sequal to the Earth-weight of a 1-kg massneeded to move an apple at 1 m/s