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Select the correct answerSIVA and Shyam are playing chess together. SIVA known the two rows in which he has to put all the pieces in but he doesn’t know how to place them. What is the probability that he puts all the pieces in the right place?Options8!/15!8!/(2𝑥15!)8!/16!(2𝑥8!)/16!

Question

Select the correct answerSIVA and Shyam are playing chess together. SIVA known the two rows in which he has to put all the pieces in but he doesn’t know how to place them. What is the probability that he puts all the pieces in the right place?Options8!/15!8!/(2𝑥15!)8!/16!(2𝑥8!)/16!

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Solution

The correct answer is 8!/16!.

Here's why:

In a game of chess, each player starts with 16 pieces: 1 king, 1 queen, 2 rooks, 2 knights, 2 bishops, and 8 pawns.

If SIVA knows the two rows where he has to place all the pieces but doesn't know how to arrange them, then he is essentially trying to arrange 16 unique items (the chess pieces) in 16 spots (the squares on the two rows).

The total number of ways to arrange 16 unique items in 16 spots is 16!, which is the denominator in our probability fraction.

The number of ways to correctly arrange the pieces is just 1 (since there's only one correct arrangement), but since each piece is not unique (for example, there are 8 identical pawns), we have to divide by the number of ways to arrange these identical pieces.

The number of ways to arrange 8 pawns is 8!, and the number of ways to arrange the 2 rooks, 2 knights, and 2 bishops (which are also identical) is 2! for each pair. So, the total number of ways to arrange the identical pieces is 8! * 2! * 2! * 2! = 8!.

So, the probability that SIVA puts all the pieces in the right place is the number of correct arrangements divided by the total number of arrangements, which is 8!/16!.

This problem has been solved

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