The time period of a simple pendulum is given by the formula T = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. This formula assumes that the only forces acting on the pendulum are gravity and the tension in the pendulum string.

When the bob is immersed in a liquid, an additional force comes into play: the buoyant force. This force is equal to the weight of the liquid displaced by the bob, and it acts upward. The net force on the bob is therefore less than its weight, which means that the effective acceleration due to gravity is less than g.

The buoyant force depends on the density of the liquid and the volume of the bob. If the density of the liquid is 1/18th of the density of brass, then the buoyant force is 1/18th of the weight of the bob. This means that the effective acceleration due to gravity is (1 - 1/18)g = 17/18g.

Substituting this into the formula for the time period gives T' = 2π√(l/(17/18g)) = T√18/17.

So, the time period of the pendulum when it is immersed in the liquid is √18/17 times the time period when it is not immersed in the liquid.

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The time period of a simple pendulum is given by the formula T = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. This formula assumes that the only forces acting on the pendulum are gravity and the tension in the pendulum string.

When the bob is immersed in a liquid, an additional force comes into play: the buoyant force. This force is equal to the weight of the liquid displaced by the bob, and it acts upward. The net force on the bob is therefore less than its weight, which means that the effective acceleration due to gravity is less than g.

The buoyant force depends on the density of the liquid and the volume of the bob. If the density of the liquid is 1/18th of the density of brass, then the buoyant force is 1/18th of the weight of the bob. This means that the effective acceleration due to gravity is (1 - 1/18)g = 17/18g.

Substituting this into the formula for the time period gives T' = 2π√(l/(17/18g)) = T√18/17.

So, the time period of the pendulum when it is immersed in the liquid is √18/17 times the time period when it is not immersed in the liquid.

Knowee AI · Accepted Answer

The time period of a simple pendulum is given by the formula T = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. This formula assumes that the only forces acting on the pendulum are gravity and the tension in the pendulum string.

When the bob is immersed in a liquid, an additional force comes into play: the buoyant force. This force is equal to the weight of the liquid displaced by the bob, and it acts upward. The net force on the bob is therefore less than its weight, which means that the effective acceleration due to gravity is less than g.

The buoyant force depends on the density of the liquid and the volume of the bob. If the density of the liquid is 1/18th of the density of brass, then the buoyant force is 1/18th of the weight of the bob. This means that the effective acceleration due to gravity is (1 - 1/18)g = 17/18g.

Substituting this into the formula for the time period gives T' = 2π√(l/(17/18g)) = T√18/17.

So, the time period of the pendulum when it is immersed in the liquid is √18/17 times the time period when it is not immersed in the liquid.

he bob of a simple pendulum is of brass and its time-period is TT. The bob is immersed in a non- viscous liquid and made to oscillate. If the density of the liquid is 18th18th of that of brass, then the time-period of the pendulum will be

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