What will be the output of following Python code snippet?str1="012"num1=2num2=0for i in range(4): num1+=2 for j in range(len(str1)): num2=num2+num1num3=num2%int(str1)print(num3)
Question
What will be the output of following Python code snippet?str1="012"num1=2num2=0for i in range(4): num1+=2 for j in range(len(str1)): num2=num2+num1num3=num2%int(str1)print(num3)
Solution
The provided Python code snippet is not correctly formatted. It should be written as follows:
str1="012"
num1=2
num2=0
for i in range(4):
num1+=2
for j in range(len(str1)):
num2=num2+num1
num3=num2%int(str1)
print(num3)
Now, let's break down the code:
str1is a string of "012",num1is an integer 2, andnum2is an integer 0.- A for loop is initiated to run 4 times. In each iteration,
num1is increased by 2. - Inside the first for loop, there is a nested for loop which runs for the length of
str1(which is 3). In each iteration of this nested loop,num2is increased by the current value ofnum1. - After all the loops,
num3is calculated as the remainder ofnum2divided by the integer value ofstr1(which is 12). - Finally,
num3is printed.
Let's calculate the values:
- After the first iteration of the outer loop,
num1is 4 andnum2is 12 (4+4+4). - After the second iteration,
num1is 6 andnum2is 42 (12+6+6+6). - After the third iteration,
num1is 8 andnum2is 90 (42+8+8+8). - After the fourth iteration,
num1is 10 andnum2is 150 (90+10+10+10).
So, num3 is the remainder of 150 divided by 12, which is 6.
Therefore, the output of the code will be 6.
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