The given grammar is:

```
G:
S - aS | AB
A - e
B - e
D - b
```

The task is to remove all the e (epsilon) productions. Epsilon productions are the productions where a variable is directly producing an epsilon.

Step 1: Identify the nullable variables. A nullable variable is a variable that can generate an epsilon. Here, A and B are nullable variables because they directly produce an epsilon.

Step 2: For each production rule, generate new rules by removing the nullable variables in all possible ways.

The new set of production rules after removing the epsilon productions is:

```
S - aS | AB | aS | a
A -
B -
D - b
```

Note: The production rules `A -` and `B -` are not valid as they do not produce anything. They are included here for completeness and to show that A and B do not produce anything after removing the epsilon productions.

So, the reduced grammar is:

```
S - aS | AB | aS | a
D - b
```

Question

The given grammar is:

```
G:
S -> aS | AB
A -> e
B -> e
D -> b
```

The task is to remove all the e (epsilon) productions. Epsilon productions are the productions where a variable is directly producing an epsilon.

Step 1: Identify the nullable variables. A nullable variable is a variable that can generate an epsilon. Here, A and B are nullable variables because they directly produce an epsilon.

Step 2: For each production rule, generate new rules by removing the nullable variables in all possible ways.

The new set of production rules after removing the epsilon productions is:

```
S -> aS | AB | aS | a
A -> 
B -> 
D -> b
```

Note: The production rules `A ->` and `B ->` are not valid as they do not produce anything. They are included here for completeness and to show that A and B do not produce anything after removing the epsilon productions.

So, the reduced grammar is:

```
S -> aS | AB | aS | a
D -> b
```

Knowee AI · Accepted Answer

The given grammar is:

```
G:
S -> aS | AB
A -> e
B -> e
D -> b
```

The task is to remove all the e (epsilon) productions. Epsilon productions are the productions where a variable is directly producing an epsilon.

Step 1: Identify the nullable variables. A nullable variable is a variable that can generate an epsilon. Here, A and B are nullable variables because they directly produce an epsilon.

Step 2: For each production rule, generate new rules by removing the nullable variables in all possible ways.

The new set of production rules after removing the epsilon productions is:

```
S -> aS | AB | aS | a
A -> 
B -> 
D -> b
```

Note: The production rules `A ->` and `B ->` are not valid as they do not produce anything. They are included here for completeness and to show that A and B do not produce anything after removing the epsilon productions.

So, the reduced grammar is:

```
S -> aS | AB | aS | a
D -> b
```

Given grammar G:S->aS| ABA-> eB-> eD-> bReduce the grammar, removing all the e productions:ans.S->aS| AB| A| B| a, D-> bS->aS| AB| A| BS->aS| AB| A| B, D-> bNone of the mentioned Previous Marked for Review Next

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