What will be the output of the following code snippet?(function(){  setTimeout(()=> console.log(1),2000); console.log(2); setTimeout(()=> console.log(3),0); console.log(4); })();*1 2 3 42 3 4 14 3 2 12 4 3 1

The output of the code snippet will be "2 4 3 1". Here's the step-by-step explanation:

1. The function is immediately invoked due to the (); at the end. This is known as an Immediately Invoked Function Expression (IIFE).

2. The first line inside the function sets a timer to log "1" after 2000 milliseconds (or 2 seconds), but it doesn't pause the execution of the rest of the function. This is because JavaScript is non-blocking, and setTimeout is an asynchronous function.

3. The next line logs "2" immediately.

4. The next line sets a timer to log "3" after 0 milliseconds. However, even though the delay is 0, it still gets placed on the event queue and will only be executed after the current execution context is finished.

5. The next line logs "4" immediately.

6. After all the synchronous code has been executed, the event queue starts executing, logging "3".

7. After 2 seconds, "1" is logged.

So, the final output is "2 4 3 1".