A tank has four emptying taps, all of equal efficiencies, but each fixed at th, th, th and th of the height of the tank respectively. Two filling taps, each of which individually can fill the tank in 200 minutes, are also connected to the tank. If the ratio of the efficiency of each emptying tap and the efficiency of each filling tap is 1 : 3, and all the six taps are opened simultaneously, in how much time will the empty tank be filled?

A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?3 hrs 15 min3 hrs 45 min4 hrs4 hrs 15 min

The figure shows Tap A, Tap B and an empty tank. Tap A can fill the empty tank in 12 minutes and Tap B can fill the empty tank in 6 minutes. Both taps are turned on at the same time. How long will it take for both taps to fill up the whole tank together?

There are three taps A, B and C in the tank. These taps can fill the tank in 10 hours, 20 hours and 25 hours respectively. At first, all three taps are opened simultaneously. After 2 hours, tap C is closed and A and B keep running. After 4 hours, tap B is also closed. The remaining tank is filled by Tap A alone. Find the percentage of the work done by Tap A itself.

There are 3 taps, A, B and C, which can fill a tank in 20, 30 and 40 minutes, respectively. The tank has 2 holes, one at the bottom of the tank, and the other at half the height of the tank. The hole at the bottom of the tank can empty it in 120 minutes and the other hole also empties at the same rate. If all the taps are opened, find the time taken to fill the tank. min min min min

Tap A, B and C can fill a tank in 16 hours, 12 hours and 20 hours respectively. The three taps are opened alternately for 1 hour each, starting with tap A at 7 am, B at 8 am and so on. At what time will the tank get filled?