A single phase full bridge diode rectifier is required to be designed for AC-DC rectification without transformer and energized from AC input of 230V 50Hz supply. without a filter capacitor. The load resistor is approximately 100 Ohm. The minimum PIV rating of each of the diodes would be:Select one:a. 400 Vb. 200 Vc. 325 Vd. 650 V
Question
A single phase full bridge diode rectifier is required to be designed for AC-DC rectification without transformer and energized from AC input of 230V 50Hz supply. without a filter capacitor. The load resistor is approximately 100 Ohm. The minimum PIV rating of each of the diodes would be:Select one:a. 400 Vb. 200 Vc. 325 Vd. 650 V
Solution
The Peak Inverse Voltage (PIV) of a diode in a full bridge rectifier is equal to the peak voltage of the input. The peak voltage can be calculated using the formula Vpeak = √2 * Vrms, where Vrms is the root mean square of the voltage.
Given that the Vrms is 230V (from the AC supply), we can substitute this into the formula:
Vpeak = √2 * 230V = approximately 325V
Therefore, the minimum PIV rating of each of the diodes should be 325V. So, the correct answer is c. 325 V.
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