Solve the equation 3, x, squared, minus, 14, x, minus, 13, equals, 2, x, squared3x 2 −14x−13=2x 2 to the nearest tenth.

The given equation seems to be incorrectly written. However, if you meant the equation to be "3x^2 - 14x - 13 = 2x^2", here's how you would solve it:

Step 1: Subtract 2x^2 from both sides to get the equation in standard form: 3x^2 - 2x^2 - 14x - 13 = 0 This simplifies to: x^2 - 14x - 13 = 0

Step 2: Now, we can solve this quadratic equation using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a). Here, a = 1, b = -14, and c = -13.

Step 3: Substitute a, b, and c into the quadratic formula: x = [14 ± sqrt((-14)^2 - 41(-13))] / (2*1) x = [14 ± sqrt(196 + 52)] / 2 x = [14 ± sqrt(248)] / 2

Step 4: Simplify the square root: x = [14 ± 15.7] / 2 This gives us two solutions: x = (14 + 15.7) / 2 = 14.85 x = (14 - 15.7) / 2 = -0.85

So, the solutions to the equation are x = 14.85 and x = -0.85, to the nearest tenth.