(b) A rectangular pontoon has a width of 6m, a length L of 12m and a draught D of 1.5min fresh water. Calculate(The weight of the pontoon"(1) The traught in sea water p = 1025kg / (m ^ 3)(H) The max load that can be carried by the pontoon in sea water if the maxallowable draught is 2.0m.

To solve this problem, we need to use the principle of buoyancy, which states that the weight of the water displaced by an object is equal to the weight of the object.

Step 1: Calculate the volume of the pontoon The volume (V) of the pontoon can be calculated using the formula for the volume of a rectangular prism, which is length (L) times width (W) times height (H). In this case, the height is the draught (D). So, V = L * W * D = 12m * 6m * 1.5m = 108 cubic meters.

Step 2: Calculate the weight of the pontoon The weight of the pontoon is equal to the weight of the water it displaces. The weight of water can be calculated by multiplying its volume by its density (ρ) and by gravity (g). In fresh water, the density is 1000 kg/m^3 and gravity is approximately 9.81 m/s^2. So, the weight (W) of the pontoon is W = V * ρ * g = 108 m^3 * 1000 kg/m^3 * 9.81 m/s^2 = 1,059,480 Newtons.

Step 3: Calculate the draught in sea water The draught in sea water can be calculated by rearranging the formula for the weight of the pontoon to solve for D. So, D = W / (ρ * g * L * W) = 1,059,480 N / (1025 kg/m^3 * 9.81 m/s^2 * 12m * 6m) = 1.43m.

Step 4: Calculate the maximum load that can be carried by the pontoon in sea water The maximum load that can be carried by the pontoon in sea water is the difference between the weight of the water displaced at the maximum allowable draught and the weight of the pontoon. The weight of the water displaced at the maximum allowable draught is V * ρ * g = 12m * 6m * 2.0m * 1025 kg/m^3 * 9.81 m/s^2 = 1,434,060 Newtons. So, the maximum load is 1,434,060 N - 1,059,480 N = 374,580 Newtons.