Which of the following numbers is divisible by each one of 3, 7, 9 and 11?a.3791b.37911c.2079d.639

To find out which number is divisible by 3, 7, 9, and 11, we need to divide each number by these divisors and see if the remainder is zero. Let's do this step by step:

a. 3791 3791 ÷ 3 = 1263 remainder 2 3791 ÷ 7 = 541 remainder 4 3791 ÷ 9 = 421 remainder 2 3791 ÷ 11 = 344 remainder 7 So, 3791 is not divisible by 3, 7, 9, and 11.

b. 37911 37911 ÷ 3 = 12637 remainder 0 37911 ÷ 7 = 5415 remainder 6 37911 ÷ 9 = 4212 remainder 3 37911 ÷ 11 = 3446 remainder 5 So, 37911 is not divisible by 3, 7, 9, and 11.

c. 2079 2079 ÷ 3 = 693 remainder 0 2079 ÷ 7 = 297 remainder 0 2079 ÷ 9 = 231 remainder 0 2079 ÷ 11 = 189 remainder 0 So, 2079 is divisible by 3, 7, 9, and 11.

d. 639 639 ÷ 3 = 213 remainder 0 639 ÷ 7 = 91 remainder 2 639 ÷ 9 = 71 remainder 0 639 ÷ 11 = 58 remainder 1 So, 639 is not divisible by 3, 7, 9, and 11.

Therefore, the number that is divisible by each one of 3, 7, 9, and 11 is 2079 (option c).