The correct arrangement of the missing lines in the program fragment for sorting an array would be:

```pascal
var
m: array [1..40] of integer;
i, buf: integer;
ind: boolean;
begin
repeat
ind:=true;
for i:=1 to 39 do
if m[i]m[i+1] then
begin
buf:=m[i];
m[i]:=m[i+1];
m[i+1]:=buf;
ind:=false;
end;
until ind;
end.
```

Here's a step-by-step explanation:

1. The `repeat..until` loop is used to keep sorting the array until no more swaps are needed. The `ind` variable is used as a flag to indicate whether a swap has occurred in the current pass. If no swaps are needed, `ind` remains `true` and the loop ends.

2. The `for` loop iterates over the array. For each pair of elements, if the current element is greater than the next one, they are swapped. This is done by temporarily storing the current element in `buf`, then replacing the current element with the next one, and finally replacing the next element with the value from `buf`.

3. If a swap has occurred, `ind` is set to `false`. This means that the array is not fully sorted yet, and another pass is needed.

4. The process repeats until a pass is made with no swaps, at which point `ind` remains `true` and the `repeat..until` loop ends. At this point, the array is fully sorted.

Question

The correct arrangement of the missing lines in the program fragment for sorting an array would be:

```pascal
var
  m: array [1..40] of integer;
  i, buf: integer;
  ind: boolean;
begin
  repeat
    ind:=true;
    for i:=1 to 39 do
      if m[i]>m[i+1] then
      begin
        buf:=m[i];
        m[i]:=m[i+1];
        m[i+1]:=buf;
        ind:=false;
      end;
  until ind;
end.
```

Here's a step-by-step explanation:

1. The `repeat..until` loop is used to keep sorting the array until no more swaps are needed. The `ind` variable is used as a flag to indicate whether a swap has occurred in the current pass. If no swaps are needed, `ind` remains `true` and the loop ends.

2. The `for` loop iterates over the array. For each pair of elements, if the current element is greater than the next one, they are swapped. This is done by temporarily storing the current element in `buf`, then replacing the current element with the next one, and finally replacing the next element with the value from `buf`.

3. If a swap has occurred, `ind` is set to `false`. This means that the array is not fully sorted yet, and another pass is needed.

4. The process repeats until a pass is made with no swaps, at which point `ind` remains `true` and the `repeat..until` loop ends. At this point, the array is fully sorted.

Knowee AI · Accepted Answer

The correct arrangement of the missing lines in the program fragment for sorting an array would be:

```pascal
var
  m: array [1..40] of integer;
  i, buf: integer;
  ind: boolean;
begin
  repeat
    ind:=true;
    for i:=1 to 39 do
      if m[i]>m[i+1] then
      begin
        buf:=m[i];
        m[i]:=m[i+1];
        m[i+1]:=buf;
        ind:=false;
      end;
  until ind;
end.
```

Here's a step-by-step explanation:

1. The `repeat..until` loop is used to keep sorting the array until no more swaps are needed. The `ind` variable is used as a flag to indicate whether a swap has occurred in the current pass. If no swaps are needed, `ind` remains `true` and the loop ends.

2. The `for` loop iterates over the array. For each pair of elements, if the current element is greater than the next one, they are swapped. This is done by temporarily storing the current element in `buf`, then replacing the current element with the next one, and finally replacing the next element with the value from `buf`.

3. If a swap has occurred, `ind` is set to `false`. This means that the array is not fully sorted yet, and another pass is needed.

4. The process repeats until a pass is made with no swaps, at which point `ind` remains `true` and the `repeat..until` loop ends. At this point, the array is fully sorted.

Question

Solution

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