Write the complete decay equation for the given nuclide in the complete AZXN notation. Refer to the periodic table for values of Z.(a)Write the complete 𝛽+ decay equation for 11C. (Use 01β to signify the following part of the equation: 𝛽+ + 𝜈e.)chemPadHelp116C → 01β+115BAn atomic number is missing from your answer or could not be identified.(b)Calculate the energy released in the decay (in MeV). (Assume 1 u = 931.5 MeV/c2.)

(a) To write the complete 𝛽+ decay equation for 11C in the complete AZXN notation, we need to determine the atomic number (Z) of the resulting nuclide.

11C has an atomic number of 6 (since it is carbon), so the resulting nuclide will have an atomic number of 5.

Therefore, the complete decay equation for 11C in the AZXN notation is:

11C → 01β+ + 115B

(b) To calculate the energy released in the decay, we can use the equation E = (m_initial - m_final) * c^2, where E is the energy released, m_initial is the initial mass, m_final is the final mass, and c is the speed of light.

The initial mass of 11C is 11 atomic mass units (u), and the final mass of 115B is 11.009305 u (since the atomic mass of boron is 10.81 u).

Using the equation E = (11 u - 11.009305 u) * (931.5 MeV/c^2), we can calculate the energy released in MeV.

E = (0.009305 u) * (931.5 MeV/c^2) E ≈ 8.67 MeV

Therefore, the energy released in the decay of 11C is approximately 8.67 MeV.