Two cars A and B travel from one city to another city, at speeds of 60 km/hr and 108 km/hour respectively. If car B takes 2 hours lesser time than car A for the journey, then what is the distance (in km) between the two cities?Options240270300330

To solve this problem, we can use the formula for time, which is distance divided by speed.

Let's denote the distance between the two cities as D (in km), the speed of car A as Sa (in km/hr), the speed of car B as Sb (in km/hr), the time taken by car A as Ta (in hours), and the time taken by car B as Tb (in hours).

From the problem, we know that:

Sa = 60 km/hr Sb = 108 km/hr Ta = Tb + 2 hours

We can express the time taken by each car to travel the distance D as follows:

Ta = D/Sa Tb = D/Sb

Substituting the known values into these equations, we get:

D/60 = D/108 + 2

To solve for D, we first need to get rid of the fractions. We can do this by multiplying the entire equation by 60*108 to get:

108D = 60D + 260108

Solving this equation for D gives:

48D = 260108 D = (260108) / 48 D = 270 km

So, the distance between the two cities is 270 km.

To solve this problem, we can use the formula for time, which is distance divided by speed.

Let's denote the distance between the two cities as D (in km), the speed of car A as Sa (in km/hr), the speed of car B as Sb (in km/hr), the time taken by car A as Ta (in hours), and the time taken by car B as Tb (in hours).

From the problem, we know that:

Sa = 60 km/hr Sb = 108 km/hr Ta = Tb + 2 hours

We can express the time taken by each car to travel the distance D as follows:

Ta = D/Sa Tb = D/Sb

Substituting the known values:

D/60 = D/108 + 2

To solve for D, we first make the denominators on the left side of the equation the same:

(108D)/6480 = (60D)/6480 + 2

Simplify the equation:

108D = 60D + 2*6480

Subtract 60D from both sides:

48D = 2*6480

Divide by 48:

D = (2*6480)/48

D = 270 km

So, the distance between the two cities is 270 km.