Divide two integers A and B, without using multiplication, division, and mod operator.Return the floor of the result of the division.Also, consider if there can be overflow cases. For overflow cases, return INT_MAX.Note: INT_MAX = 2^31 - 1Problem ConstraintsINT_MIN <= A, B <= INT_MAXB != 0Input FormatThe first argument is an integer A.The second argument is an integer B.Output FormatReturn an integer equal to A / B.Example InputA = 5B = 2
Question
Divide two integers A and B, without using multiplication, division, and mod operator.Return the floor of the result of the division.Also, consider if there can be overflow cases. For overflow cases, return INT_MAX.Note: INT_MAX = 2^31 - 1Problem ConstraintsINT_MIN <= A, B <= INT_MAXB != 0Input FormatThe first argument is an integer A.The second argument is an integer B.Output FormatReturn an integer equal to A / B.Example InputA = 5B = 2
Solution
Here is a Python solution for the problem:
def divide(A, B):
INT_MAX = 2**31 - 1
if A == 0:
return 0
if B == 1:
return A
if B == -1:
if A > INT_MAX:
return INT_MAX
else:
return -A
sign = -1 if ((A < 0) ^ (B < 0)) else 1
dividend = abs(A)
divisor = abs(B)
quotient = 0
while (dividend >= divisor):
temp = divisor
i = 1
while (dividend >= temp):
dividend -= temp
quotient += i
i <<= 1
temp <<= 1
return sign * quotient
This function works by subtracting the divisor from the dividend until the dividend is less than the divisor. The quotient is then the number of times the divisor was subtracted. The function also handles edge cases such as when the divisor is 1 or -1, and when the dividend is 0. It also takes into account the sign of the result, which is negative if the dividend and divisor have different signs, and positive otherwise.
Similar Questions
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