The antibiotic called azithromycin created a clear area with a diameter of 21 mm.Calcualte the cross-sectional area in mm._____ mm2Use the maths keyboard to write your answer in standard form and to three significant figures.
Question
The antibiotic called azithromycin created a clear area with a diameter of 21 mm.Calcualte the cross-sectional area in mm._____ mm2Use the maths keyboard to write your answer in standard form and to three significant figures.
Solution
To calculate the cross-sectional area of the clear area created by the antibiotic azithromycin, we can use the formula for the area of a circle, which is πr².
Given that the diameter of the clear area is 21 mm, the radius (r) would be half of the diameter, which is 21/2 = 10.5 mm.
Substituting the radius into the formula, we get:
Area = π(10.5 mm)² = π(110.25 mm²) = 346.36 mm²
So, the cross-sectional area of the clear area created by the antibiotic azithromycin is approximately 346 mm² to three significant figures.
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