What is the output of the following code snippet?#include <stdio.h>int main() {    int x = 5;    if (x > 2) {        printf("A");        if (x < 5) {            printf("B");        }    } else {        printf("C");    }    return 0;}

The output of the given code snippet will be "A".

Here's the step by step explanation:

1. The integer variable x is initialized with the value 5.
2. The first if statement checks if x is greater than 2. Since 5 is greater than 2, the condition is true. Therefore, the program enters the first if block and prints "A".
3. Inside the first if block, there is a nested if statement that checks if x is less than 5. Since x is not less than 5 (it's equal to 5), this condition is false. Therefore, "B" is not printed.
4. The else block is not executed because the condition of the first if statement was true.
5. The program ends with a return statement return 0;, signaling successful execution.

So, the output is "A".