Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number. Options :3101720
Question
Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number. Options :3101720
Solution
Sure, let's solve this step by step.
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Let's denote the number we're looking for as x. According to the problem, we have the equation: x + 17 = 60/x.
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To solve this equation, we first need to get rid of the fraction. We can do this by multiplying every term by x, which gives us: x^2 + 17x = 60.
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Now, we can rearrange this equation to look like a quadratic equation: x^2 + 17x - 60 = 0.
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The next step is to factor this equation. The factors of -60 that add up to 17 are 20 and -3. So, we can write the equation as: (x - 20)(x + 3) = 0.
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Setting each factor equal to zero gives the solutions x = 20 and x = -3.
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However, the problem asks for a positive number, so the only valid solution is x = 20.
So, the positive number that satisfies the given condition is 20.
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