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What is the output of the following code:#include <stdio.h>void main(){ char *s = "hi"; char *p = s * 3; printf("%c\t%c", *p, s[1]);}h il eCompilation failsl h

Question

What is the output of the following code:#include <stdio.h>void main(){ char *s = "hi"; char *p = s * 3; printf("%c\t%c", *p, s[1]);}h il eCompilation failsl h

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Solution

To determine the output of the given code, let's analyze it step by step:

  1. The code includes the standard input/output library, stdio.h.

  2. The main function is defined with a return type of void, indicating that it does not return a value.

  3. Inside the main function: a. A character pointer s is declared and initialized with the string "hi". b. Another character pointer p is declared and assigned the value of s multiplied by 3. However, multiplying a pointer by an integer is not a valid operation in most programming languages, including C. This line of code will result in a compilation error.

  4. The code attempts to print the value of *p and s[1] using the printf function. However, since there is a compilation error, the code will not be able to execute this line.

Therefore, the output of the code is a compilation failure.

This problem has been solved

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