(0,8/3), (1, 3) and (82, 30) area?​

To find the area of a triangle given its vertices, you can use the formula:

Area = 1/2 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|

where (x1, y1), (x2, y2), and (x3, y3) are the coordinates of the vertices of the triangle.

Here, the coordinates are (0, 8/3), (1, 3), and (82, 30).

So, x1 = 0, y1 = 8/3, x2 = 1, y2 = 3, x3 = 82, and y3 = 30.

Substitute these values into the formula:

Area = 1/2 * |0*(3 - 30) + 1*(30 - 8/3) + 82*(8/3 - 3)|

Simplify the expression inside the absolute value:

Area = 1/2 * |-0 + 22/3 + 82*5/3|

Area = 1/2 * |22/3 + 410/3|

Area = 1/2 * |432/3|

Area = 1/2 * 144

Area = 72

So, the area of the triangle is 72 square units.