Two chords are drawn in the circle such that one chord is 24 cm away from the centre and other is 10 cm away from the centre. If the radius of the circle is 26 cm, find the length of the chords.Choices:- 48cm,20cm 23cm,45cm 44cm,56cm 20cm,67cm

The length of a chord can be found using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this case, the hypotenuse is the radius of the circle, and one of the other sides is the distance from the center of the circle to the chord. The length of the chord is the remaining side, and it can be found by rearranging the Pythagorean theorem as follows:

Length of chord = √(radius² - distance²)

For the chord that is 24 cm away from the center:

Length of chord = √(26² - 24²) = √(676 - 576) = √100 = 10 cm

So, the length of the chord is 2 * 10 = 20 cm (since the formula gives the length of half the chord).

For the chord that is 10 cm away from the center:

Length of chord = √(26² - 10²) = √(676 - 100) = √576 = 24 cm

So, the length of the chord is 2 * 24 = 48 cm.

Therefore, the lengths of the chords are 20 cm and 48 cm. The correct choice is 48cm, 20cm.