Two quizzes were administered to the class. There were no absentees on both days when the quizzes were administered. In Quiz 1. the ratio of passes to failures is 3:1. In Quiz 2, the ratio of passes to failures is 4:1. If the number of failures in Quiz 2 is one less than that in Quiz 1. how many students are in the class?
Question
Two quizzes were administered to the class. There were no absentees on both days when the quizzes were administered. In Quiz 1. the ratio of passes to failures is 3:1. In Quiz 2, the ratio of passes to failures is 4:1. If the number of failures in Quiz 2 is one less than that in Quiz 1. how many students are in the class?
Solution
Let's solve this step by step:
Step 1: Let's denote the number of students who failed Quiz 1 as F1 and the number of students who passed Quiz 1 as P1. According to the problem, the ratio of passes to failures in Quiz 1 is 3:1, so we can write this as P1/F1 = 3/1, or P1 = 3F1.
Step 2: Similarly, let's denote the number of students who failed Quiz 2 as F2 and the number of students who passed Quiz 2 as P2. The ratio of passes to failures in Quiz 2 is 4:1, so we can write this as P2/F2 = 4/1, or P2 = 4F2.
Step 3: The problem also tells us that the number of failures in Quiz 2 is one less than that in Quiz 1, so we can write this as F2 = F1 - 1.
Step 4: The total number of students in the class is the sum of the number of passes and failures in either Quiz 1 or Quiz 2 (since there were no absentees), so we can write this as Total = P1 + F1 = P2 + F2.
Step 5: Substituting P1 = 3F1 and P2 = 4F2 into the equation from Step 4 gives us Total = 3F1 + F1 = 4F2 + F2.
Step 6: Substituting F2 = F1 - 1 into the equation from Step 5 gives us Total = 4F1 - 4 + F1 - 1 = 4F1.
Step 7: Solving for F1 gives us F1 = 5.
Step 8: Substituting F1 = 5 into the equation P1 = 3F1 gives us P1 = 15.
Step 9: Therefore, the total number of students in the class is Total = P1 + F1 = 15 + 5 = 20.
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