Isooctane =, C8H18 d0.692gmL is used as the fuel during a test of a new automobile engine. How much energy in kJ is released by complete combustion of 21.9gal of isooctane to gases =ΔHorxn×−5.44103kJmol? Be sure your answer has the correct number of significant figures.
Question
Isooctane =, C8H18 d0.692gmL is used as the fuel during a test of a new automobile engine. How much energy in kJ is released by complete combustion of 21.9gal of isooctane to gases =ΔHorxn×−5.44103kJmol? Be sure your answer has the correct number of significant figures.
Solution
To solve this problem, we need to follow these steps:
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Convert the volume of isooctane from gallons to liters. There are approximately 3.78541 liters in a gallon, so 21.9 gallons is about 82.8 liters.
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Convert the volume of isooctane to mass. The density of isooctane is 0.692 g/mL, and there are 1000 mL in a liter, so the mass of 82.8 liters of isooctane is about 57273.6 grams.
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Convert the mass of isooctane to moles. The molar mass of isooctane (C8H18) is about 114.22 g/mol, so there are about 501.4 moles of isooctane in 57273.6 grams.
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Calculate the energy released by the combustion of isooctane. The heat of reaction (ΔHrxn) is -5.44 x 10^3 kJ/mol, so the energy released by the combustion of 501.4 moles of isooctane is about -2.73 x 10^6 kJ.
So, the complete combustion of 21.9 gallons of isooctane releases about -2.73 x 10^6 kJ of energy.
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