Oil, of density 883 kg/m3 and kinematic viscosity 5.68 x 10-5 m2/s, flows through a pipe 9.5 cm internal diameter at a volume flow rate of 0.05 (m3/s) .Determine the average velocity in m/s.
Question
Oil, of density 883 kg/m3 and kinematic viscosity 5.68 x 10-5 m2/s, flows through a pipe 9.5 cm internal diameter at a volume flow rate of 0.05 (m3/s) .Determine the average velocity in m/s.
Solution
The average velocity of a fluid flowing through a pipe can be calculated using the formula:
V = Q/A
where: V is the average velocity, Q is the volume flow rate, and A is the cross-sectional area of the pipe.
Given: Q = 0.05 m³/s (volume flow rate) d = 9.5 cm = 0.095 m (internal diameter of the pipe)
We can calculate the cross-sectional area (A) of the pipe using the formula for the area of a circle:
A = π(d/2)²
Substituting the given diameter:
A = π(0.095/2)² = 0.00707 m²
Now we can calculate the average velocity (V):
V = Q/A = 0.05 m³/s / 0.00707 m² = 7.07 m/s
So, the average velocity of the oil flowing through the pipe is approximately 7.07 m/s.
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