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Oil, of density 883 kg/m3 and kinematic viscosity 5.68 x 10-5 m2/s, flows through a pipe 9.5 cm internal diameter at a volume flow rate of 0.05 (m3/s) .Determine the average velocity in m/s.

Question

Oil, of density 883 kg/m3 and kinematic viscosity 5.68 x 10-5 m2/s, flows through a pipe 9.5 cm internal diameter at a volume flow rate of 0.05 (m3/s) .Determine the average velocity in m/s.

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Solution

The average velocity of a fluid flowing through a pipe can be calculated using the formula:

V = Q/A

where: V is the average velocity, Q is the volume flow rate, and A is the cross-sectional area of the pipe.

Given: Q = 0.05 m³/s (volume flow rate) d = 9.5 cm = 0.095 m (internal diameter of the pipe)

We can calculate the cross-sectional area (A) of the pipe using the formula for the area of a circle:

A = π(d/2)²

Substituting the given diameter:

A = π(0.095/2)² = 0.00707 m²

Now we can calculate the average velocity (V):

V = Q/A = 0.05 m³/s / 0.00707 m² = 7.07 m/s

So, the average velocity of the oil flowing through the pipe is approximately 7.07 m/s.

This problem has been solved

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