PQRST is a pentagon in which all the interior angles are unequal. A circle of radius 'r' is inscribed in each of the vertices. Find the area of portion of circles falling inside the pentagon.

The problem you've presented is quite complex and requires additional information to solve. In a regular pentagon, all the interior angles are equal, but in this case, the pentagon PQRST has unequal interior angles. Therefore, we cannot use the formula for the area of a regular pentagon to solve this problem.

However, if we assume that the circles inscribed at each vertex of the pentagon are tangent to each other and to the sides of the pentagon, we can say that the portion of the circles inside the pentagon forms a star-like shape.

The area of this star-like shape can be calculated by subtracting the area of the pentagon from the total area of the five circles.

The area of a circle is given by the formula πr², so the total area of the five circles is 5πr².

To calculate the area of the pentagon, we would need to know the length of its sides or the measures of its angles.

Once we have the area of the pentagon, we can subtract it from the total area of the circles to find the area of the portion of the circles inside the pentagon.

Please note that this solution assumes that the circles are tangent to each other and to the sides of the pentagon. If this is not the case, the problem cannot be solved without additional information.