The relation between bit and byte in digital logic is 1 byte = 10 bits 1 byte = 16 bits 1 byte = 8 bits 1 byte = 2 bits

A byte consists ofOption A:Eight bitsOption B:Four bitsOption C:Sixteen bitsOption D:One bit

Reading Material Binary OperatorsA binary digit (0 or 1) is also called as bit.There are certain operations you can do on a pair of bits, and one such operator is AND (represented by symbol ‘&’).​If you are given 2 bits ‘a’ and ‘b’, then the value of ‘a&b’ comes as follows: a b a&b0 0 00 1 01 0 01 1 1​In other words, a&b = 1 if a and b are both equal to 1.​Given 2 binary numbers, you can do bitwise AND (pad 0s to make them the same length and then ‘AND’ between corresponding bits).Example 1: if I ask you what is AND between 1010 and 11, then you follow the following steps:​ - Step 1: Make both numbers equal size by padding 0s. So, our numbers become 1010 and 0011. - Step 2: Now take AND of corresponding bits like the following:​   1010& 0011——–   0010​Hence, the answer is 0010.​Question:​You are given a list of binary numbers [110011, 111010, 11011, 1110, 11000, 101010, 11110].You can freely choose any 2 numbers from this list. You have to choose them so that the AND of those 2 numbers is maximized. What is the max AND value possible?Note: In your answer, ensure first bit is 1 (for example, if the answer is 10, please put 10 as the answer and not 010 or 0010).

The two symbols 0 and 1 are known as bits in a binary system.

In computing terminology, "bit" is derived from the phrase "Binary digIT."a.Falseb.True

Binary OperatorsA binary digit (0 or 1) is also called as bit.There are certain operations you can do on a pair of bits, and one such operator is XOR (represented by symbol ^).If you are given 2 bits a and b, then the value of a^b comes as follows:a b a^b0 0 00 1 11 0 11 1 0In other words, a^b = 1 if a and b are different, otherwise it is 0.Given 2 binary numbers, you can do bitwise XOR (pad 0s to make them the same length and then xor between corresponding bits).Example 1: if I ask you what is XOR between 1010 and 11, then you follow the following steps:Step 1: Make both numbers equal size by padding 0s. So, our numbers become 1010 and 0011.Step 2: Now take XOR of corresponding bits like the following: 1010 ^ 0011 -------- 1001Hence, the answer is 1001.Given 2 decimal numbers, you can do bitwise XOR.If I ask you what is the XOR between 3 and 4 then you can convert them to binary first and apply the approach explained above.Example 2: 3^43 in binary is 114 in binary is 100 011^100----- 111Hence, the answer is 111 which is 7 in decimal.So, 3^4 = 7QuestionIf x ^ 21 = 34, and x ^ 31 = 40, find x.