(a) If the order of the choices matters, we use the permutation formula. The number of ways to choose 3 letters from 4, without replacement and where order matters, is given by P(4,3) = 4! / (4-3)! = 4*3*2 = 24 ways.

(b) If the order of the choices does not matter, we use the combination formula. The number of ways to choose 3 letters from 4, without replacement and where order does not matter, is given by C(4,3) = 4! / [3!(4-3)!] = 4 ways.

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(a) If the order of the choices matters, we use the permutation formula. The number of ways to choose 3 letters from 4, without replacement and where order matters, is given by P(4,3) = 4! / (4-3)! = 4*3*2 = 24 ways.

(b) If the order of the choices does not matter, we use the combination formula. The number of ways to choose 3 letters from 4, without replacement and where order does not matter, is given by C(4,3) = 4! / [3!(4-3)!] = 4 ways.

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(a) If the order of the choices matters, we use the permutation formula. The number of ways to choose 3 letters from 4, without replacement and where order matters, is given by P(4,3) = 4! / (4-3)! = 4*3*2 = 24 ways.

(b) If the order of the choices does not matter, we use the combination formula. The number of ways to choose 3 letters from 4, without replacement and where order does not matter, is given by C(4,3) = 4! / [3!(4-3)!] = 4 ways.

Suppose we want to choose 3 letters, without replacement, from the 4 letters A, B, C, and D.(If necessary, consult a list of formulas.)(a) How many ways can this be done, if the order of the choices matters?(b) How many ways can this be done, if the order of the choices does not matter?

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