Write the ionic equation for the reaction between lead(II) nitrate(aq) + magnesium sulfate(aq) magnesium nitrate(aq) + lead(II) sulfate(s)
Question
Write the ionic equation for the reaction between lead(II) nitrate(aq) + magnesium sulfate(aq) magnesium nitrate(aq) + lead(II) sulfate(s)
Solution
Sure, here is the ionic equation for the reaction:
Step 1: Write the balanced molecular equation: Pb(NO3)2(aq) + MgSO4(aq) → Mg(NO3)2(aq) + PbSO4(s)
Step 2: Write the ionic equation: Pb2+(aq) + 2NO3-(aq) + Mg2+(aq) + SO4^2-(aq) → Mg2+(aq) + 2NO3-(aq) + PbSO4(s)
Step 3: Cross out the spectator ions that are present on both sides of the ionic equation: Pb2+(aq) + SO4^2-(aq) → PbSO4(s)
So, the net ionic equation is: Pb2+(aq) + SO4^2-(aq) → PbSO4(s)
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