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Write the ionic equation for the reaction between lead(II) nitrate(aq) + magnesium sulfate(aq)  magnesium nitrate(aq) + lead(II)                                                                                                                                     sulfate(s)

Question

Write the ionic equation for the reaction between lead(II) nitrate(aq) + magnesium sulfate(aq)  magnesium nitrate(aq) + lead(II)                                                                                                                                     sulfate(s)

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Solution

Sure, here is the ionic equation for the reaction:

Step 1: Write the balanced molecular equation: Pb(NO3)2(aq) + MgSO4(aq) → Mg(NO3)2(aq) + PbSO4(s)

Step 2: Write the ionic equation: Pb2+(aq) + 2NO3-(aq) + Mg2+(aq) + SO4^2-(aq) → Mg2+(aq) + 2NO3-(aq) + PbSO4(s)

Step 3: Cross out the spectator ions that are present on both sides of the ionic equation: Pb2+(aq) + SO4^2-(aq) → PbSO4(s)

So, the net ionic equation is: Pb2+(aq) + SO4^2-(aq) → PbSO4(s)

This problem has been solved

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