Problem:define a recursive function to generate all Anagrams of a given stringTest Case 1:Enter a word: abcabcacbbacbcacabcbaTest Case 2:Enter a word: ababba
Question
Problem:define a recursive function to generate all Anagrams of a given stringTest Case 1:Enter a word: abcabcacbbacbcacabcbaTest Case 2:Enter a word: ababba
Solution
Sure, here is a Python solution for generating all anagrams of a given string using recursion:
def generate_anagrams(word):
if len(word) <= 1:
return [word]
# Get all permutations of length N-1
permutations = generate_anagrams(word[1:])
char = word[0]
result = []
# Iterate through all permutations of length N-1
for perm in permutations:
# Insert the character into every possible location
for i in range(len(perm)+1):
result.append(perm[:i] + char + perm[i:])
return result
You can test this function with your test cases like this:
print(generate_anagrams('abcabcacbbacbcacabcba'))
print(generate_anagrams('ababba'))
Please note that the number of anagrams for a string of length N is N factorial (N!). So, for long strings, this function may take a very long time to run and may consume a large amount of memory.
Similar Questions
ecursive functionsdefine a recursive function to generate all possiblesubsequences of a given stringTest Case 1:Enter a string: abccbbcaacababcTest Case 2:Enter a string: abbaabSample Test CasesTest Case 1:Expected Output:Enter·a·string:·abccbbcaacababcTest Case 2:Expected Output:Enter·a·string:·abbaab
Given a string S. the task is to determine if there exists another string that is an anagram of S.An anagram is a word or phrase formed by rearranging the letters of another word or phrase. For example "seekg" is an anagram of "geeks".Example 1:Input: S = "ab"Output: YESExplanation:The string "ba" is not identical to S and is an anagram of S
Two strings, and , are called anagrams if they contain all the same characters in the same frequencies. For this challenge, the test is not case-sensitive. For example, the anagrams of CAT are CAT, ACT, tac, TCA, aTC, and CtA.Function DescriptionComplete the isAnagram function in the editor.isAnagram has the following parameters:string a: the first stringstring b: the second stringReturnsboolean: If and are case-insensitive anagrams, return true. Otherwise, return false.Input FormatThe first line contains a string .The second line contains a string .ConstraintsStrings and consist of English alphabetic characters.The comparison should NOT be case sensitive.
You are given a string s, which is known to be a concatenation of anagrams of some string t.Return the minimum possible length of the string t.An anagram is formed by rearranging the letters of a string. For example, "aab", "aba", and, "baa" are anagrams of "aab". Example 1:Input: s = "abba"Output: 2Explanation:One possible string t could be "ba".Example 2:Input: s = "cdef"Output: 4Explanation:One possible string t could be "cdef", notice that t can be equal to s. Constraints:1 <= s.length <= 105s consist only of lowercase English letters.
You are given N strings of length M, count the number of anagramic groups. An anagramic group is a list of strings which are anagrams of each other.Input FormatThe first line of input contains T - the number of test cases. In each test case, the first line contains N - the number of strings and M - the length of each string, separated by a space. The N subsequent lines each contain a string of length M.Output FormatFor each test case, print the count of the number of anagramic groups in the given N strings, separated by a new line.Constraints1 <= T <= 1001 <= N <= 1001 <= M <= 1000'a' <= str[i] <= 'z'ExampleInput25 4artsrankstarrantrats9 5teslastartslatesaltetartsasterarsonastlenorseOutput35ExplanationTest-Case 1The strings "arts", "star" and "rats" can be grouped together because they are anagrams of each other.The total number of such groups is 3 and the groups are {"arts", "rats", "star"}, {"rant"} and {"rank"}.
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