A cannon ball is shot at 40 degrees to the horizontal with an initial speed of 68 ms-1. How far will the ball travel horizontally before hitting the ground? Assume the ground is flat and the acceleration due to gravity is 9.8 ms-2Question 5Select one:465 m284 m68 m120 m
Question
A cannon ball is shot at 40 degrees to the horizontal with an initial speed of 68 ms-1. How far will the ball travel horizontally before hitting the ground? Assume the ground is flat and the acceleration due to gravity is 9.8 ms-2Question 5Select one:465 m284 m68 m120 m
Solution
To solve this problem, we need to use the equations of motion.
First, we need to find the time of flight (t). The time of flight of a projectile motion can be calculated using the formula:
t = 2u*sin(θ)/g
where: u = initial speed = 68 m/s θ = angle of projection = 40 degrees g = acceleration due to gravity = 9.8 m/s²
Substituting the given values into the formula, we get:
t = 268sin(40)/9.8 t ≈ 8.8 seconds
Next, we need to find the horizontal distance (d) travelled by the ball. The horizontal distance can be calculated using the formula:
d = u*cos(θ)*t
Substituting the given values into the formula, we get:
d = 68*cos(40)*8.8 d ≈ 465 m
So, the ball will travel approximately 465 meters horizontally before hitting the ground.
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