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The triangle in the figure has vertices at points P(0, 0), Q(0, 6.5), and R(3, 2).  What is the perimeter of the triangle? Group of answer choices12.81217.215.15

Question

The triangle in the figure has vertices at points P(0, 0), Q(0, 6.5), and R(3, 2).  What is the perimeter of the triangle? Group of answer choices12.81217.215.15

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Solution

To find the perimeter of the triangle, we need to find the length of all three sides and add them together.

The length of a side of a triangle with endpoints (x1, y1) and (x2, y2) can be found using the distance formula: √[(x2-x1)² + (y2-y1)²].

  1. For side PQ: The coordinates are P(0,0) and Q(0,6.5). So, the length of PQ is √[(0-0)² + (6.5-0)²] = 6.5 units.

  2. For side QR: The coordinates are Q(0,6.5) and R(3,2). So, the length of QR is √[(3-0)² + (2-6.5)²] = √[9 + 20.25] = √29.25 = 5.41 units (approx).

  3. For side RP: The coordinates are R(3,2) and P(0,0). So, the length of RP is √[(0-3)² + (0-2)²] = √[9 + 4] = √13 = 3.61 units (approx).

Now, add all these lengths to get the perimeter of the triangle.

Perimeter = PQ + QR + RP = 6.5 + 5.41 + 3.61 = 15.52 units (approx).

So, the closest answer to this is 15.15.

This problem has been solved

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