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Calculate the ΔH of a reaction with bond strengths of bonds broken equal to 60 kcal/mol and 107 kcal/mol and bond strengths of bond formed equal to 110 kcal/mol and 88 kcal/mol.Select answer from the options below151 kcal/mol31 kcal/mol-31 kcal/mol-245 kcal/molSave for LaterSubmit Answer

Question

Calculate the ΔH of a reaction with bond strengths of bonds broken equal to 60 kcal/mol and 107 kcal/mol and bond strengths of bond formed equal to 110 kcal/mol and 88 kcal/mol.Select answer from the options below151 kcal/mol31 kcal/mol-31 kcal/mol-245 kcal/molSave for LaterSubmit Answer

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Solution

To calculate the ΔH of a reaction, you need to subtract the total energy of the bonds formed from the total energy of the bonds broken.

First, add up the energy of the bonds broken: 60 kcal/mol + 107 kcal/mol = 167 kcal/mol.

Next, add up the energy of the bonds formed: 110 kcal/mol + 88 kcal/mol = 198 kcal/mol.

Finally, subtract the energy of the bonds formed from the energy of the bonds broken: 167 kcal/mol - 198 kcal/mol = -31 kcal/mol.

So, the ΔH of the reaction is -31 kcal/mol.

This problem has been solved

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