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A new car is purchased for 22300 dollars. The value of the car depreciates at 10.25% per year. What will the value of the car be, to the nearest cent, after 6 years?

Question

A new car is purchased for 22300 dollars. The value of the car depreciates at 10.25% per year. What will the value of the car be, to the nearest cent, after 6 years?

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Solution

To solve this problem, we will use the formula for exponential decay, which is:

V = P * (1 - r)^t

where:

  • V is the final value of the car
  • P is the initial value of the car
  • r is the rate of depreciation
  • t is the time in years

Given in the problem: P = $22,300 r = 10.25% = 0.1025 (as a decimal) t = 6 years

Substitute these values into the formula:

V = 22300 * (1 - 0.1025)^6

First, calculate the value inside the parentheses:

1 - 0.1025 = 0.8975

Then, raise this result to the power of 6:

0.8975^6 = 0.558405

Finally, multiply this result by the initial value of the car:

V = 22300 * 0.558405 = $12452.63

So, the value of the car after 6 years, to the nearest cent, will be approximately $12,452.63.

This problem has been solved

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