Select the correct answerA number when divided by a divisor left reminder 23. When twice of the number was divided by the same divisor, reminder was 11. what is the divisor?Options252123534

Let's solve this step by step:

1. Let's denote the number as 'a' and the divisor as 'd'. According to the problem, when 'a' is divided by 'd', the remainder is 23. We can write this as: a = kd + 23, where 'k' is the quotient.

2. The problem also states that when twice the number (2a) is divided by the same divisor 'd', the remainder is 11. We can write this as: 2a = ld + 11, where 'l' is the new quotient.

3. We can substitute the value of 'a' from the first equation into the second equation: 2(kd + 23) = ld + 11.

4. Simplifying this gives: 2kd + 46 = ld + 11.

5. Rearranging terms gives: ld - 2kd = 46 - 11.

6. Simplifying further gives: d(l - 2k) = 35.

7. Since 'd', 'l', and 'k' are all integers (because they represent a divisor and quotients), the only possible value for 'd' that satisfies this equation, given the options, is 35.

So, the divisor is 35.