The value of tan9o−tan27o−tan63o+tan81o is _____.
Question
The value of tan9o−tan27o−tan63o+tan81o is _____.
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Solution
The given expression is tan9° - tan27° - tan63° + tan81°.
We know that tan(90° - θ) = cot θ. So we can write the expression as follows:
tan9° - tan27° - tan(90° - 27°) + tan(90° - 9°)
This simplifies to:
tan9° - tan27° - cot27° + cot9°
We also know that tan θ - cot θ = 0. So the expression simplifies to:
0 - 0 = 0
So, the value of tan9° - tan27° - tan63° + tan81° is 0.
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