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Use the limit process to find the slope of the graph of the function at the specified point. Use a graphing utility to confirm your result.f(x) = 2x − 6x2,    (3, −48)

Question

Use the limit process to find the slope of the graph of the function at the specified point. Use a graphing utility to confirm your result.f(x) = 2x − 6x2,    (3, −48)

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Solution

To find the slope of the graph of the function at a specified point using the limit process, we need to find the derivative of the function. The derivative of a function at a certain point gives the slope of the tangent line at that point.

The function is f(x) = 2x - 6x^2.

The derivative of a function f(x) is given by the limit:

f'(x) = lim(h->0) [f(x+h) - f(x)] / h

Let's find the derivative of f(x):

f'(x) = lim(h->0) [(2(x+h) - 6(x+h)^2) - (2x - 6x^2)] / h

Simplify the expression inside the brackets:

= lim(h->0) [(2x + 2h - 6x^2 - 6h^2) - (2x - 6x^2)] / h

= lim(h->0) [2h - 6h^2] / h

Factor out h:

= lim(h->0) h(2 - 6h) / h

Cancel out h:

= lim(h->0) 2 - 6h

As h approaches 0, the limit is 2.

So, the derivative of the function f(x) = 2x - 6x^2 is f'(x) = 2.

The slope of the graph of the function at the point (3, -48) is therefore f'(3) = 2.

You can confirm this result using a graphing utility by graphing the function and its derivative and checking the slope at the point (3, -48).

This problem has been solved

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