To find the inverse Laplace transform of 12/(4-3s), we first need to rewrite the function in a form that we can recognize from the Laplace transform table.

The Laplace transform of an exponential function e^(at) is 1/(s-a). So, we need to rewrite our function to match this form.

We can rewrite 12/(4-3s) as -4/(s-(4/3)).

Now, we can see that it matches the form 1/(s-a) with a = 4/3 and a constant multiplier of -4.

So, the inverse Laplace transform of 12/(4-3s) is -4e^(4t/3).

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To find the inverse Laplace transform of 12/(4-3s), we first need to rewrite the function in a form that we can recognize from the Laplace transform table.

The Laplace transform of an exponential function e^(at) is 1/(s-a). So, we need to rewrite our function to match this form.

We can rewrite 12/(4-3s) as -4/(s-(4/3)).

Now, we can see that it matches the form 1/(s-a) with a = 4/3 and a constant multiplier of -4.

So, the inverse Laplace transform of 12/(4-3s) is -4e^(4t/3).

Knowee AI · Accepted Answer

To find the inverse Laplace transform of 12/(4-3s), we first need to rewrite the function in a form that we can recognize from the Laplace transform table.

The Laplace transform of an exponential function e^(at) is 1/(s-a). So, we need to rewrite our function to match this form.

We can rewrite 12/(4-3s) as -4/(s-(4/3)).

Now, we can see that it matches the form 1/(s-a) with a = 4/3 and a constant multiplier of -4.

So, the inverse Laplace transform of 12/(4-3s) is -4e^(4t/3).

find the inverse laplace transform of 12/(4-3s)

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