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why the above 2 lines of code is incorrect:

Question

why the above 2 lines of code is incorrect:

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Solution

I'm sorry, but you haven't provided any lines of code. Could you please provide the code you're referring to?

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What is the output for the following code?

Question 9Which of the following is an mistake in code which has not yet been activated?1 pointLatent errorFaultEffective errorFailure

The following code gives this incorrect output.Which of the following statements about what is causing the error is true? (select all valid answers)carrie@ubuntu:/debugging$ cat main.c #include <stdio.h> /** * main - debugging example * Return: 0 */ int main(void) { int i; int j; for (i = 0; i < 10; i++) { j = 0; while (j < 10) { printf("%d", j); } printf("\n"); } return (0); } carrie@ubuntu:/debugging$carrie@ubuntu:/debugging$ gcc -Wall -Werror -Wextra -pedantic main.c carrie@ubuntu:/debugging$ ./a.out0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 <...>^Ccarrie@ubuntu:/debugging$j never increments so it will always be less than 10j never increments so it is always going to print 0j is always equal to i so the loop will never endI don't know

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