Calculate the molarity of a solution containing KCl and water whose osmotic pressure at 21°C is 13.3 kPa. Assume complete dissociation of the salt.Question 8Select one:0.01 M0.005 M0.0002 M0.08 M0.0027 M
Question
Calculate the molarity of a solution containing KCl and water whose osmotic pressure at 21°C is 13.3 kPa. Assume complete dissociation of the salt.Question 8Select one:0.01 M0.005 M0.0002 M0.08 M0.0027 M
Solution
To calculate the molarity of a solution using osmotic pressure, we can use the formula:
π = nRT/V
where: π is the osmotic pressure, n is the number of moles of solute, R is the ideal gas constant, T is the temperature in Kelvin, V is the volume of the solution in liters.
Given: π = 13.3 kPa = 13.3 x 10^3 Pa (since 1 kPa = 10^3 Pa) T = 21°C = 21 + 273.15 = 294.15 K (since Kelvin = Celsius + 273.15) R = 8.314 Pa.m^3/mol.K (ideal gas constant)
We are looking for n/V which is the molarity (M). So, rearranging the formula to solve for M gives us:
M = π / RT
Substituting the given values into the formula:
M = (13.3 x 10^3 Pa) / (8.314 Pa.m^3/mol.K x 294.15 K)
After calculating the above expression, we get the molarity of the solution.
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