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What is the volume of a cylinder, in cubic in, with a height of 8in and a base diameter of 4in? Round to the nearest tenths place

Question

What is the volume of a cylinder, in cubic in, with a height of 8in and a base diameter of 4in? Round to the nearest tenths place

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Solution

To find the volume of a cylinder, we use the formula:

V=πr2h V = \pi r^2 h

where V V is the volume, r r is the radius of the base, and h h is the height of the cylinder.

  1. First, determine the radius of the base. The diameter is given as 4 inches, so the radius r r is half of the diameter: r=42=2 inches r = \frac{4}{2} = 2 \text{ inches}

  2. The height h h is given as 8 inches.

  3. Substitute the values of r r and h h into the volume formula: V=π(2)2(8) V = \pi (2)^2 (8)

  4. Calculate the square of the radius: (2)2=4 (2)^2 = 4

  5. Multiply by the height: 4×8=32 4 \times 8 = 32

  6. Multiply by π \pi : V=32π V = 32\pi

  7. Use the approximate value of π \pi (3.14159) to find the volume: V32×3.14159 V \approx 32 \times 3.14159

  8. Perform the multiplication: V100.53056 V \approx 100.53056

  9. Round to the nearest tenths place: V100.5 V \approx 100.5

So, the volume of the cylinder is approximately 100.5 cubic inches.

This problem has been solved

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