What is the rate constant of a reaction if rate = 1.5 (mol/L)/s, [A] is 1 M, [B] is 3 M, m = 2, and n = 1?A.0.17B.4.5C.13.5D.0.5SUBMITarrow_backPREVIOUS
Question
What is the rate constant of a reaction if rate = 1.5 (mol/L)/s, [A] is 1 M, [B] is 3 M, m = 2, and n = 1?A.0.17B.4.5C.13.5D.0.5SUBMITarrow_backPREVIOUS
Solution
The rate constant (k) of a reaction can be calculated using the rate law equation:
Rate = k[A]^m[B]^n
Where: Rate is the rate of reaction, [A] and [B] are the concentrations of the reactants, m and n are the reaction orders with respect to [A] and [B], and k is the rate constant.
Given: Rate = 1.5 mol/L/s, [A] = 1 M, [B] = 3 M, m = 2, and n = 1.
Substitute these values into the rate law equation:
1.5 = k(1)^2(3)^1 1.5 = k13 1.5 = 3k
Solve for k:
k = 1.5 / 3 k = 0.5
So, the rate constant of the reaction is 0.5. The correct answer is D.0.5.
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