The average of 3 consecutive natural numbers is k. This means that the second number in this sequence is k.

Let's denote these numbers as (k-1), k, (k+1).

If we add two more consecutive numbers to this sequence, they will be (k+2) and (k+3).

The new sequence of numbers is (k-1), k, (k+1), (k+2), (k+3).

To find the new average, we add up all these numbers and divide by the total number of numbers.

So, the new average is [(k-1) + k + (k+1) + (k+2) + (k+3)] / 5 = (5k + 5) / 5 = k + 1.

Therefore, the new average becomes k + 1.

Question

The average of 3 consecutive natural numbers is k. This means that the second number in this sequence is k.

Let's denote these numbers as (k-1), k, (k+1).

If we add two more consecutive numbers to this sequence, they will be (k+2) and (k+3).

The new sequence of numbers is (k-1), k, (k+1), (k+2), (k+3).

To find the new average, we add up all these numbers and divide by the total number of numbers.

So, the new average is [(k-1) + k + (k+1) + (k+2) + (k+3)] / 5 = (5k + 5) / 5 = k + 1.

Therefore, the new average becomes k + 1.

Knowee AI · Accepted Answer

The average of 3 consecutive natural numbers is k. This means that the second number in this sequence is k.

Let's denote these numbers as (k-1), k, (k+1).

If we add two more consecutive numbers to this sequence, they will be (k+2) and (k+3).

The new sequence of numbers is (k-1), k, (k+1), (k+2), (k+3).

To find the new average, we add up all these numbers and divide by the total number of numbers.

So, the new average is [(k-1) + k + (k+1) + (k+2) + (k+3)] / 5 = (5k + 5) / 5 = k + 1.

Therefore, the new average becomes k + 1.

The average of 3 consecutive natural numbers (which are in increasing order) is k. If two more consecutive numbers, just next to the first set of numbers, is added, then the new average becomes?