Given a list of numbers of list, write a Python program to create a list of tuples having first element as the number and second element as the cube of the number.                                                                                   example                                                                                                                                                                                           Input: list = [1, 2, 3]             Output: [(1, 1), (2, 8), (3, 27)]

Sure, here is a step by step guide on how to solve this problem in Python:

1. First, you need to define your list of numbers. For example:

list_numbers = [1, 2, 3]

2. Next, you need to create a new list that will store your tuples. You can do this by using a list comprehension. In the list comprehension, for each number in your original list, you create a tuple. The first element of the tuple is the number itself and the second element is the cube of the number. Here is how you can do it:

list_tuples = [(num, num**3) for num in list_numbers]

In this line of code, num**3 is used to calculate the cube of the number. The ** operator is the exponentiation operator in Python.

3. Finally, you can print your new list to check the result:

print(list_tuples)

When you run this program, it will output:

[(1, 1), (2, 8), (3, 27)]

This means that the number 1 is cubed to 1, the number 2 is cubed to 8, and the number 3 is cubed to 27.