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Stations M and N are 276 km part. At the exact same time, a train starts from M and other from N towards N and M respectively.These trains meet after 12 hours.The train travelling from M to N is slower by 14 km/hr in comparison to the other train. What is speed of slower train?5 km/hr13 km/hr7 km/hr4.5 km/hr

Question

Stations M and N are 276 km part. At the exact same time, a train starts from M and other from N towards N and M respectively.These trains meet after 12 hours.The train travelling from M to N is slower by 14 km/hr in comparison to the other train. What is speed of slower train?5 km/hr13 km/hr7 km/hr4.5 km/hr

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Solution

Let's denote the speed of the slower train (from M to N) as x km/hr. Then the speed of the faster train (from N to M) is x + 14 km/hr.

Since the trains meet after 12 hours, we can set up the following equation using the formula distance = speed * time:

12x (the distance the slower train travels in 12 hours) + 12(x + 14) (the distance the faster train travels in 12 hours) = 276 km (the total distance between the two stations).

Solving this equation will give us the speed of the slower train.

First, simplify the equation:

12x + 12x + 168 = 276

Combine like terms:

24x + 168 = 276

Subtract 168 from both sides:

24x = 108

Finally, divide both sides by 24 to solve for x:

x = 108 / 24 = 4.5

So, the speed of the slower train is 4.5 km/hr.

This problem has been solved

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