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I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If Ikeep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute?(

Question

I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If Ikeep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute?(

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Solution

The problem can be solved using the concept of Least Common Multiple (LCM) and adding the remainder.

Step 1: Find the LCM of 2, 3, and 4. The LCM of 2, 3, and 4 is 12.

Step 2: Check if the LCM plus the remainder (which is 1 in this case) is divisible by 5. 12 + 1 = 13, which is not divisible by 5.

Step 3: If it's not divisible, add the LCM until you find a number that, when added to the remainder, is divisible by 5.

So, we get: 12 (LCM) * 1 + 1 (remainder) = 13 12 * 2 + 1 = 25 12 * 3 + 1 = 37 12 * 4 + 1 = 49 12 * 5 + 1 = 61

Step 4: The first number that is divisible by 5 when 1 is added is 25. So, the minimum number of sweets you have to pack and distribute is 25.

This problem has been solved

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